Question

How many molecules of SO2 gas would occupy 4.15 L at STP?

A) 6.02 x 10^23 molecules
B) 2.01 x 10^23 molecules
C) 3.01 x 10^23 molecules
D) 4.01 x 10^23 molecules

Answer 1

At STP, one mole of any gas occupies 22.4 L. To calculate the number of molecules of SO2 gas in 4.15 L at STP, divide the given volume by the molar volume, then multiply by Avogadro's number.

Step-by-step explanation:

At STP (standard temperature and pressure), one mole of any gas occupies 22.4 L. We can use this information to calculate the number of molecules of SO2 gas that would occupy 4.15 L at STP.

First, we need to determine how many moles of SO2 gas would occupy 4.15 L. We can do this by dividing the given volume by the molar volume:

4.15 L / 22.4 L/mol = 0.185 moles

Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to calculate the number of molecules:

0.185 moles x 6.02 x 10^23 molecules/mol = 1.11 x 10^23 molecules

Therefore, the answer is A) 6.02 x 10^23 molecules.