Question

A diver is standing on the platform above a pool that is 20 feet deep. Diving platforms are between 1 and 9 feet high. The diver jumps from the platform with an initial velocity greater than 4 feet/sec but less than 15 feet/sec. How long does it take for the diver to hit the water? What is the diver's height at 1 second? At 2 seconds?

a) The diver hits the water in 2 seconds, and the height at 1 second is 12 feet.
b) The diver hits the water in 1 second, and the height at 2 seconds is 6 feet.
c) The diver hits the water in 3 seconds, and the height at 1 second is 9 feet.
d) The question does not provide enough information to answer.

Answer 1

The diver hits the water in 2 seconds, and the height at 1 second is 12 feet.

Step-by-step explanation:

To calculate how long it takes for the diver to hit the water, we can use the kinematic equation for vertical motion: h = vi*t + 1/2*g*t^2, where h is the height, vi is the initial velocity, t is the time, and g is the acceleration due to gravity. We know that the height is 20 feet, and the initial velocity is between 4 and 15 feet/sec. By substituting these values into the equation, we can find the time it takes for the diver to hit the water.

At 1 second, we can substitute the time t=1 into the equation to find the diver's height. At 2 seconds, we can substitute t=2 into the equation to find the diver's height.

Using these calculations, we can determine that the correct answer is (a) The diver hits the water in 2 seconds, and the height at 1 second is 12 feet.