Question

A factory lift is used to raise a load of 14,325 N on a piston that has an area of 706.8 cm². How much pressure does the lift's engine need to exert on the hydraulic fluid to lift the required load?

A) 202.57 Pa
B) 202.57 kPa
C) 2.02 MPa
D) 20.26 kPa

Answer 1

The pressure the lift's engine must exert is calculated using the formula pressure = force / area. After converting the area to square meters, the result is 202.57 kPa, which corresponds to option B.

Step-by-step explanation:

To determine the pressure the lift's engine needs to exert on the hydraulic fluid to lift the load of 14,325 N, you can use the formula for pressure, which is pressure (P) = force (F) divided by the area (A). First, convert the area from cm² to m² to match the SI units for pressure (pascals).

Area in m²: 706.8 cm² × (1 m² / 10,000 cm²) = 0.07068 m²

Next, calculate the pressure:

Pressure (P) = Force (F) / Area (A) = 14,325 N / 0.07068 m² = 202,571.4286 Pa

Since 1 kPa is equivalent to 1,000 Pa, the pressure in kilopascals is:

202,571.4286 Pa ÷ 1,000 = 202.57 kPa

Therefore, the correct answer to the student's question is 202.57 kPa, which corresponds to option B.