Question

A sample of aluminum has a mass of 13.0 grams. The sample underwent a change in thermal energy of 3500. joules. Calculate how much its temperature will change during this process.

A) 269.2°C
B) 130.1°C
C) 50.0°C
D) 7.7°C

Answer 1

The temperature of the aluminum will change by approximately 299.1°C when it undergoes a change in thermal energy of 3500 joules and none of the given options are correct.

Step-by-step explanation:

To calculate how much the temperature of the aluminum will change, we can use the formula for heat transfer Q = mcΔT, where:

• Q is the heat transferred (in joules)
• m is the mass (in kilograms)
• c is the specific heat capacity (in J/kg°C)
• ΔT is the change in temperature (in °C)

The specific heat capacity for aluminum is given as 900 J/kg°C. To find ΔT, we rearrange the formula to ΔT = Q / (mc).

First, we will need to convert the mass from grams to kilograms: 13.0 g = 0.013 kg.

ΔT = 3500 J / (0.013 kg * 900 J/kg°C) = 3500 / 11.7 = 299.1°C.

Therefore, the temperature of the aluminum will change by approximately 299.1°C. None of the provided options are correct.