Final answer:
The range of values of p in the equation y = 2^2 - 12x - p > 0 is p ≤ -12x, so the correct option is p < -18.
Step-by-step explanation:
To find the range of values of p, we need to solve the equation y = 2^2 - 12x - p > 0 for p. Let's analyze the expression 2^2 - 12x - p. Since the exponent is 2 and positive, the term 2^2 is always positive. The term -12x can be positive or negative depending on the value of x. To make sure the entire expression is greater than 0, we want the sum of the terms -12x and -p to be less than or equal to 0. So, the range of values for p can be expressed as p ≤ -12x. Therefore, the correct option is (a) p < -18.