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18 votes
18 votes
josh goes to a bank and cashes a $250 check. he receives 16 bills consisting of all $20 bills and $10 bills. how many of each kind are there?

User Anthonypliu
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2 Answers

22 votes
22 votes

Final answer:

Josh received 9 $20 bills and 7 $10 bills.

Step-by-step explanation:

To solve this problem, let's assume that Josh receives x $20 bills and y $10 bills. Since he receives 16 bills in total, we can write an equation based on the given information:



x + y = 16
Each $20 bill is worth 20 dollars, so the total value of the $20 bills is 20x. Each $10 bill is worth 10 dollars, so the total value of the $10 bills is 10y. According to the problem, Josh cashed a $250 check, so the total value of the bills must be equal to $250:



20x + 10y = 250
To solve this system of equations, we can use substitution or elimination method. Let's use substitution:



From the first equation, we have x = 16 - y. Substituting this into the second equation:



20(16 - y) + 10y = 250
320 - 20y + 10y = 250
-10y = 250 - 320
-10y = -70
y = -70 / -10
y = 7
Now, substitute the value of y back into the first equation:



x + 7 = 16
x = 16 - 7
x = 9



Therefore, Josh received 9 $20 bills and 7 $10 bills.

User Jonathan Lyon
by
2.8k points
16 votes
16 votes

Answer:

9 = 20

7 = 10

Step-by-step explanation:

User Travis Schettler
by
2.9k points