Question

Sonny is twice as old as Wale. Four years ago, he was four times as old as Wale. When will the sum of their ages be 66? Explain.

A) In 20 years, because that's when the sum of their ages will be 66.

B) In 10 years, because Sonny will be five times as old as Wale at that point.

C) In 12 years, because their ages will be 66 then.

D) In 8 years, because that's when Sonny's age will be four times Wale's age, like it was four years ago.

Answer 1

To solve for when the sum of Sonny and Wale's ages will be 66, we can set up equations based on the given information and solve them simultaneously.

Step-by-step explanation:

To solve this problem, we can use algebraic equations. Let's denote Sonny's age as S and Wale's age as W. From the given information, we know that Sonny is twice as old as Wale, so we can write the equation S = 2W. We also know that four years ago, Sonny was four times as old as Wale, so we can write the equation S - 4 = 4(W - 4).

Now, we can solve these two equations simultaneously. Substituting the value of S from the first equation into the second equation, we get 2W - 4 = 4(W - 4). Solving this equation, we find that W = 8. Substituting this value back into the first equation, we get S = 16.

To find when the sum of their ages will be 66, we can set up the equation S + W = 66 and solve for the values of S and W that satisfy this equation. Substituting the values we found earlier, we get 16 + 8 = 66. This equation is not true, so the correct answer is none of the given options.