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Circle the element in the following list that has a natural or already existing stable octet and therefore does not participate in bonding:

a) K
b) Br
c) Kr
d) Cu
e) Lr

User Siddarth G
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1 Answer

7 votes

Final answer:

Krypton (Kr) is the element that has an existing stable octet and does not generally participate in bonding because it is a noble gas with a full valence shell.

Step-by-step explanation:

The element in the list that has a natural or already existing stable octet and therefore does not participate in bonding is Kr (krypton). This is because krypton is a noble gas, which means it has a full valence shell, usually two for helium and eight electrons for the other noble gases. This full valence shell gives these elements a natural stability, and they have little tendency to react and form bonds with other elements.

User Rpilkey
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