Question

If 588 grams of FeS₂ is allowed to react with 352 grams of O₂ according to the following unbalanced equation, how many grams of Fe₂O₃ are produced?

FeS₂ + O₂ → Fe₂O₃ + SO₂
a) 400 grams
b) 512 grams
c) 480 grams
d) 544 grams

Answer 1

The grams of Fe2O3 produced is 588 grams.

Step-by-step explanation:

To determine the grams of Fe2O3 produced, we need to first balance the equation. We have:

FeS2 + O2 → Fe2O3 + SO2

From the balanced equation, we can see that the stoichiometric ratio between FeS2 and Fe2O3 is 1:1. So, if 588 grams of FeS2 is reacted, 588 grams of Fe2O3 will be produced.

Therefore, the answer is 588 grams.