Question

Stan was running a on a trail in a wooded area next to his house. He generally runs at a pace of 3 m/s. While Stan was running he realized a dog started chasing him. To get away from the dog, Stan had to run at a pace of 10 m/s for about 2 minutes. What was Stan's acceleration during this time? (Round to the nearest hundredth)

A) 0.06 m/s
B) 0.06 m/s²
C) 3.5 m/s²
D) 3.5 m/s

Answer 1

Stan's acceleration when increasing his running speed from 3 m/s to 10 m/s over a period of 2 minutes (120 seconds) is calculated to be 0.06 m/s², after rounding to the nearest hundredth.

Step-by-step explanation:

To calculate Stan's acceleration during the time he increased his pace from 3 m/s to 10 m/s, we can use the formula for acceleration, which is a change in velocity (\(\Delta v\)) divided by the time taken for the change (\(\Delta t\)). The change in velocity is the final velocity minus the initial velocity. In this case, his final velocity is 10 m/s, and his initial velocity is 3 m/s, so the change in velocity is 10 m/s - 3 m/s = 7 m/s. The time taken for this change is 2 minutes, which is 120 seconds. Using the formula for acceleration:

a = \(\Delta v / \Delta t\) = (10 m/s - 3 m/s) / 120 s = 7 m/s / 120 s = 0.05833 m/s2

Rounding to the nearest hundredth, Stan's acceleration is 0.06 m/s2. Therefore, the correct answer is B) 0.06 m/s2.