Question

Jeff and Sher bought a TV together for $128. If Jeff paid $36 more than Sher, how much did each pay?

a) Jeff $92, Sher $36
b) Jeff $80, Sher $48
c) Jeff $46, Sher $82
d) Jeff $82, Sher $46

Answer 1

Jeff paid $82 and Sher paid $46 (option D).

Step-by-step explanation:

Let's set up an equation to represent the problem.

Let's say Jeff paid x dollars and Sher paid y dollars.

From the given information, we know that Jeff paid $36 more than Sher, so we can say:

x = y + $36.

We also know that Jeff and Sher together paid $128, so we can set up another equation:

x + y = $128.

Now we can solve the system of equations:

Substituting the first equation into the second equation, we get (y + $36) + y

= $128.

Combining like terms, we get 2y + $36 = $128.

Subtracting $36 from both sides, we get 2y = $92.

Dividing both sides by 2, we get y = $46.

Substituting the value of y back into the first equation, we get x = $46 + $36

= $82.

Therefore, Jeff paid $82 and Sher paid $46.