Final answer:
The complement of set A (A'), considering the universal set S, consists of all numbers from S that are not in A, which would be {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}. None of the provided answers fully match the correct complement.
Step-by-step explanation:
In mathematics, the complement of a set S, denoted as S', includes all the elements that are in the universal set but not in set S. Given the universal set S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19} and set A = {2, 4, 6, 8, 10, 12, 14, 16, 18}, to find the complement of A (A'), we list all the numbers from the universal set S that are not in A.
Thus, A' consists of {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}. Note that among the answer choices, only B seems to partially represent the complement of A but misses some values. So, if it were an option, the correct complement of set A would include the odds numbers and prime numbers 11, 13, 15, 17, and 19 that are missing from option B.