Final answer:
To calculate the heat released by sour patch kids in a calorimeter, we use the formula q = mcΔT. With the water's temperature rise of 39.3°C, the mass of 100 grams, and the specific heat capacity of water (1 cal/g°C), the heat released is 3930 calories or approximately 4 Calories. The closest provided answer is 3950 calories or 3.95 Calories, rounded to 4 Calories.
Step-by-step explanation:
To determine how much heat is released by a sample of sour patch kids burned in a calorimeter, we need to calculate the heat absorbed by the water when its temperature increases. The equation for this calculation is q = mcΔT, where q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
The specific heat capacity of water is 1 calorie/g°C; the mass of the water is 100 grams, and the temperature increase (ΔT) is 62.8°C - 23.5°C = 39.3°C. Thus, we can calculate the heat released (q) by the sour patch kids using this formula:
q = mcΔT = (100 g)(1 cal/g°C)(39.3°C) = 3930 calories. Converting calories to Calories (1 Calorie = 1000 calories), we get 3.93 Calories, which rounds to approximately 4 Calories (with a capital C).
The closest answer matching the provided options is B. 3950 calories, which when converted to Calories is approximately 3.95 Calories. Let's round it to 4 Calories because Calories are generally expressed to the nearest whole number.