247,681 views
22 votes
22 votes
The perimeter of the triangle is 10x^2-6x+1 and the side lengths are 5x+7 and 8x^2-4x.What is the length of the missing side?

User Faraj
by
3.1k points

1 Answer

13 votes
13 votes

Answer:

2x^2-7x-6

Explanation:

P=A+B+C=10x^2-6x+1

A=5x+7

B=8x^2-4x

C=?

  • C=P-(A+B)

= 10x^2-6x+1-(5x+7+8x^2-4x)

=10x^2-6x+1-(8x^2-6x+7)

=2x^2-7x-6

User Rdnobrega
by
3.2k points