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Given f(n) = -2n^3 + 3n^2 and g(n) = -2n - 4, find f(n) + g(n).

A. -2n^3 + 3n^2 - 2n - 4
B. -2n^3 + 3n^2 + 2n + 4
C. -4n^3 + 3n^2 - 2n - 4
D. -2n^3 + n^2 - 2n - 8

1 Answer

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Final answer:

The sum of the functions f(n) = -2n^3 + 3n^2 and g(n) = -2n - 4 is -2n^3 + 3n^2 - 2n - 4, corresponding to option A.

Step-by-step explanation:

To find the sum of the two functions f(n) and g(n), we simply add the two functions together term by term.

The function f(n) is given as -2n^3 + 3n^2, and the function g(n) is -2n - 4. Adding these functions together:

f(n) + g(n) = (-2n^3 + 3n^2) + (-2n - 4)


= -2n^3 + 3n^2 - 2n - 4

Thus, the sum of f(n) and g(n) is -2n^3 + 3n^2 - 2n - 4, which corresponds to option A.

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