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A lawn sprinkler located at the corner of a yard is set to rotate 135 degrees and water an area of 200 square feet. What is the distance that the sprinkler can project water out? Round to the nearest integer.

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Final answer:

The sprinkler can project water approximately 9.6 feet out, which rounds to 10 feet when looking for the nearest integer.

Step-by-step explanation:

To determine the distance that the sprinkler can project water out, we can use the formula for the area of a sector of a circle: A = (\theta/360) \times \pi r^2, where A is the area watered by the sprinkler, θ is the angle of rotation in degrees, and r is the radius of the circle, which corresponds to the distance the water travels.

The area A is given as 200 square feet and the angle θ is 135 degrees. Plugging these values into the formula and solving for r gives us:

A = (135/360) × π r^2
200 = (135/360) × π r^2
200 ÷ ((135/360) × π) = r^2
r^2 = 200 ÷ (0.375 × π)
r = √(200 ÷ (0.375 × π))
r ≈ 9.6 feet
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