Final answer:
The energy of a photon with a wavelength of 1.06 x 10^-6 m is 1.88 x 10^-19 J.
Step-by-step explanation:
The energy of a photon can be calculated using the equation E = hf, where E is the energy, h is Planck's constant (6.63 x 10^-34 J·s), and f is the frequency. Since the problem provides the wavelength (1.06 x 10^-6 m), we can use the relationship c = fλ, where c is the speed of light (3 x 10^8 m/s) and λ is the wavelength, to find the frequency: f = c / λ. Plugging in the values, we get f = (3 x 10^8 m/s) / (1.06 x 10^-6 m) = 2.83 x 10^14 Hz. Now we can calculate the energy using E = hf: E = (6.63 x 10^-34 J·s) * (2.83 x 10^14 Hz) = 1.88 x 10^-19 J.