Question

Solve using the quadratic formula 2m² + 4m + 5 = 0.

A) m = -1 ± i√4
B) m = -2 ± i√4
C) m = -4 ± i√2
D) m = -2 ± i√6

Answer 1

To solve the quadratic equation 2m² + 4m + 5 = 0 using the quadratic formula, we substitute the values of a = 2, b = 4, and c = 5 into the formula. Simplifying the equation, we find that the solutions for m involve imaginary numbers: m = -1 ± i√6. None of the option is correct

Step-by-step explanation:

We can solve the quadratic equation 2m² + 4m + 5 = 0 using the quadratic formula.

The quadratic formula states that if we have an equation of the form ax² + bx + c = 0, then the solutions for x can be found using the formula:

x = (-b ± √(b² - 4ac)) / 2a

For the given equation, a = 2, b = 4, and c = 5.

Plugging these values into the quadratic formula, we get:

m = (-4 ± √(4² - 4(2)(5))) / (2(2))

Simplifying further, we have:

m = (-4 ± √(16 - 40)) / 4

m = (-4 ± √(-24)) / 4

Since the discriminant (√(-24)) is negative, the solutions will involve imaginary numbers.

Therefore, the correct answer is:

m = -1 ± i√6

None of the option is correct