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If a rocket accelerates from rest at a rate of 50 meters per second for 10 seconds, the distance it will cover during this time is ______

a) 500m
b) 250m
c) 2500m
d) none
e) 500m

1 Answer

4 votes

Final answer:

The distance covered by a rocket accelerating from rest at a rate of 50 m/s² for 10 seconds is 2500 meters, calculated using the kinematic formula for constant acceleration.

Step-by-step explanation:

To find the distance covered by a rocket accelerating from rest, we can use the formula for distance under constant acceleration, which is given by d = ut + (1/2)at2, where d is distance, u is initial velocity, a is acceleration, and t is time.

Since the rocket starts from rest, its initial velocity u is 0. The acceleration a is given as 50 meters per second squared, and the time t is 10 seconds. Plugging these values into the equation:

d = 0 * 10 + (1/2) * 50 * 102 = 0 + 2500

Therefore, the distance covered by the rocket is 2500 meters.

So the correct answer is c) 2500m.

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