Question

What is the equation of the line that passes through the point (-4,-4) and has a slope of 5/4?

A) y = (5/4)x + 4
B) y = (4/5)x - 4
C) y = (5/4)x - 4
D) y = (4/5)x + 4

Answer 1

The equation of the line that passes through the point (-4,-4) and has a slope of 5/4 is y = (5/4)x + 4.

Step-by-step explanation:

The equation of the line that passes through the point (-4,-4) and has a slope of 5/4 can be found using the point-slope form of a linear equation. This form is given by y - y1 = m(x - x1), where (x1, y1) represents the given point and m represents the slope. Plugging in the values (-4,-4) for (x1, y1) and 5/4 for m, we can write the equation as y - (-4) = (5/4)(x - (-4)). This simplifies to y + 4 = (5/4)(x + 4). Finally, we can rewrite this equation in slope-intercept form (y = mx + b), by subtracting 4 from both sides, to get the equation y = (5/4)x + 4.