Question

A car traveling at 5.3 m/s accelerates at the rate of +0.56 m/s2 for an interval of 4.9 s. Find vf. In m/s

Answer 1

To calculate the final velocity (vf) of the car, the equation vf = vi + (a × t) is used, resulting in a final velocity of 8.044 m/s after 4.9 seconds of acceleration.

Step-by-step explanation:

To find vf, the final velocity of the car, we can use the equation of motion which relates initial velocity (vi), acceleration (a), and time (t):

vf = vi + (a × t)

Given that the initial velocity vi is 5.3 m/s, the acceleration a is 0.56 m/s2, and the time t is 4.9 s, we can substitute these values into the equation:

vf = 5.3 m/s + (0.56 m/s2 × 4.9 s)

vf = 5.3 m/s + 2.744 m/s

vf = 8.044 m/s

The final velocity vf of the car after accelerating for 4.9 seconds is 8.044 m/s.