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Write the equation in slope-intercept form of a line that has a slope of 1/3 and passes through the point (-6, 0).y=1/3xy=1/3x-6y=1/3x-2y=1/3x+2

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Final answer:

To write the equation of a line in slope-intercept form, use the slope and a point. For this line with a slope of 1/3 and passing through (-6, 0), the equation is y=(1/3)x+2.

Step-by-step explanation:

To write the equation of a line in slope-intercept form, which is y = mx + b, we need to find the values of m (slope) and b (y-intercept).

Given a slope of 1/3, we know that m=1/3.

We also know that the line passes through the point (-6, 0). To find the y-intercept, we can substitute the X and Y values into the equation y = mx + b and solve for b.

By substituting x=-6 and y=0, we have 0 = (1/3)(-6) + b. Solving for b, we get b = 2.

Therefore, the equation in slope-intercept form of the line with a slope of 1/3 and passes through the point (-6, 0) is y = (1/3)x + 2.

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