Question

An aqueous solution of glucose has density 1.18g / mL. Which statement(s) about this solution is/are correct if its Molarity of solution is 1 M?

a. Molality of the solution is more than 1 M.
b. (W/V)% of glucose is 18%.
c. (W/W)% of glucose is 15.25 (approx.).
d. (W/V)% of glucose is more than (W/W)% of glucose.

Answer 1

We analyze the molality and percentage concentrations of a glucose solution using its molarity and density. Options involve comparing molality to molarity and calculating weight/volume and weight/weight percentages, considering the measured density.

Step-by-step explanation:

The question centers around the calculation of the molality and percentage concentrations of a glucose solution based on its molarity and density. Understanding the relations between these different concentration measurements is fundamental to solution chemistry.

Analysis of Options

1. Molality being higher than molarity would depend on the solution's density and the molecular weight of glucose. Since density is given, the mass of solvent can be determined and used to calculate the molality.
2. (W/V)% of glucose being 18% suggests that for every 100 mL of solution, there are 18 grams of glucose, which can be calculated using the density and molarity.
3. (W/W)% of glucose requires knowing the mass of glucose and the total mass of the solution.
4. (W/V)% being higher than (W/W)% indicates that the volume-based concentration is greater than the mass-based concentration, taking the solution's density into account.