Final answer:
The 10th term of the arithmetic sequence is 9x + 37.
Step-by-step explanation:
The given arithmetic sequence is 4x-7, 9x-11, 14x-15.
To find the 10th term, we can use the formula for the nth term of an arithmetic sequence: an = a1 + (n-1)d.
In this case, the first term, a1, is 4x-7 and the common difference, d, is 5x-4. Plugging in the values, we have:
a10 = (4x-7) + (10-1)(5x-4)
= 9x + 37
Therefore, the 10th term of the arithmetic sequence 4x-7, 9x-11, 14x-15 is 9x + 37.