The distance from point P to line L is **3 units**.
To find the distance from point P to line L, we'll follow these steps:
1. **Determine the slope of line L:**
- The slope of line L is 0, as it's a vertical line with the same x-coordinates for both points.
2. **Find the equation of the perpendicular line passing through point P:**
- Since line L is vertical, the perpendicular line will be horizontal.
- The equation of the perpendicular line passing through P(1, 6) will be y = 6 (as y remains constant for a horizontal line).
3. **Find the point of intersection of the perpendicular line with line L:**
- The perpendicular line (y = 6) intersects line L at the point (4, 6), as it has the same y-coordinate as P and the same x-coordinate as the points on line L.
4. **Calculate the distance between point P and the intersection point:**
- The distance between P(1, 6) and (4, 6) is simply the difference in their x-coordinates:
- Distance = |1 - 4| = 3 units
Therefore, the distance from point P to line L is **3 units**.
The probable question may be:
Find the distance from point P to line L. Line L contains points (4, -1) and (4, 9). point P has coordinates (1, 6).