Question

An F-15 fighter jet is in a dog fight with a Mig-23. In order to execute a loop, it accelerates from 40ms to 70ms in about 3 seconds. How fast did it accelerate?

A) 10 m/s
B) 15 m/s
C) 20 m/s
D) 30 m/s

Answer 1

The acceleration of the F-15 fighter jet as it increases its speed from 40 m/s to 70 m/s in 3 seconds is calculated to be 10 m/s², corresponding to answer option A).

Step-by-step explanation:

The student asked how fast an F-15 fighter jet accelerates if it speeds up from 40 m/s to 70 m/s in about 3 seconds. To find the acceleration, you can use the formula for acceleration a = (v_f - v_i) / t, where v_f is the final velocity (70 m/s), v_i is the initial velocity (40 m/s), and t is the time (3 seconds). Plugging in the values, the calculation is (70 m/s - 40 m/s) / 3 s = 30 m/s / 3 s = 10 m/s². Therefore, the F-15's acceleration is 10 m/s², which corresponds to answer option A).