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What is the value of f(6) f (n) = { n/2 i f n is even { 3n+1 i f n is odd?

A) 3
B) 9
C) 12
D) 18

User Gnosis
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1 Answer

6 votes

Final answer:

The value of f(6) is 3, as 6 is an even number and according to the given function, f(n) for an even number is n/2.

Step-by-step explanation:

The student has asked for the value of f(6) for the given function f(n), where f(n) is equal to n/2 if n is even and equal to 3n + 1 if n is odd.

Since 6 is an even number, we apply the rule for even numbers:

The function f(n) is defined as follows:

If n is even, f(n) = n/2

If n is odd, f(n) = 3n+1

To find the value of f(6), we need to plug in the value 6 into the function. Since 6 is even, we use the first case:

f(6) = 6/2 = 3

Therefore, the value of f(6) is 3.

f(6) = 6 / 2 = 3

Therefore, f(6) is 3.

User Leopold Joy
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