Question

Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 2 x + 1 = 0

a. x = -1
c. x = -3
b. x = 1 or x = -3
d. x = 2 or x = -1

Answer 1

Answer: A

Explanation:

x = -1

Answer 2

a. x = -1

Explanation:

For a quadratic equation like this it is usually more easier to use the factorisation method so I'm sorry but I can't do the tables of x and y method

`ax^(2) +bx+c`

In factorisation, you find a number that multiplies to give c but also adds or subtracts to give b so in this example it would be:

`x^(2) +2x+1=0`

1: 1 × 1 = 1

So 1 times 1 gives 1 but then 1+1 gives 2 which is the correct match for this quadratic

`(x+1)(x+1)=0`

Now to solve it you take one bracket and you solve it using the 0

`x+1=0\\x= -1`

Because both the equations are the same the answer would be the same

:)