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How much energy must be absorbed by 20.0 g of water to increase its temperature from 183 °C to 303 °C? (Cp of H2O = 4.184 J/g °C)

User Dsb
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1 Answer

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Final answer:

To determine the amount of energy required to increase the temperature of water from 183 °C to 303 °C, we can use the equation: q = m * c * ΔT, where q is the energy absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Substituting the given values, we can calculate the energy absorbed as 10044.8 J.

Step-by-step explanation:

To determine the amount of energy required to increase the temperature of water from 183 °C to 303 °C, we can use the equation:


q = m * c * ΔT


where:



  • q is the energy absorbed (in joules)

  • m is the mass of water (in grams)

  • c is the specific heat capacity of water (in J/g °C)

  • ΔT is the change in temperature (in °C)


Substituting the given values:



  • m = 20.0 g

  • c = 4.184 J/g °C

  • ΔT = 303 °C - 183 °C = 120 °C


We can calculate the energy absorbed by multiplying the mass, specific heat capacity, and change in temperature:


q = 20.0 g * 4.184 J/g °C * 120 °C = 10044.8 J


Therefore, 20.0 g of water must absorb 10044.8 J of energy to increase its temperature from 183 °C to 303 °C.

User Avigayil
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