Final answer:
The potential energy at the car's starting position of one-meter height is 0.981 joules. The kinetic energy at the bottom of the hill, with a speed of 0.80 m/sec, is 0.032 joules.
Step-by-step explanation:
The student is investigating the potential energy of a car at its starting position at the top of a hill and its kinetic energy when it reaches the bottom. To calculate the potential energy (PE) at the starting position, we use the formula PE = mgh, where m is the mass of the car (0.1 kg), g is the acceleration due to gravity (9.81 m/s²), and h is the height of the hill (1 meter). Thus, PE = 0.1 kg × 9.81 m/s² × 1 m = 0.981 joules.
To calculate the kinetic energy (KE) at the bottom of the hill, we use the formula KE = 1/2 mv², where m is the mass of the car (0.1 kg) and v is its velocity (0.80 m/s). Therefore, KE = 0.5 × 0.1 kg × (0.80 m/s)² = 0.032 joules.