Question

A 200 g piece of iron is heated to 100°C. It is then dropped into water to bring its temperature down to 22°C. What is the amount of heat transferred to water?**

a) (2.35 times 10^4) J

b) (1.25 times 10^4) J

c) (3.42 times 10^4) J

d) (1.56 times 10^4) J

Answer 1

The amount of heat transferred to water can be calculated using the specific heat equation.

Step-by-step explanation:

The amount of heat transferred to water can be calculated using the equation:

Q = (specific heat) × (mass) × (change in temperature)

Where Q is the amount of heat transferred, the specific heat for water is 4.184 J/g°C, the mass is 200 g, and the change in temperature is 100°C - 22°C = 78°C.

Substituting the values into the equation:

Q = (4.184 J/g°C) × (200 g) × (78°C) = 65,491.2 J (or approximately 6.55 × 10^4 J)

Therefore, the correct answer is (c) (3.42 × 10^4) J.