The force at which the cat falls is calculated using Newton's second law of motion, F = mg, with a mass of 5.00 kg and the acceleration due to gravity of 9.80 m/s², resulting in a force of 49.0 N.
The question is about determining the force at which a cat falls. According to Newton's second law of motion, the force (F) acting on an object is equal to the mass (m) of the object multiplied by the acceleration due to gravity (g), which can be expressed as F = mg. If we assume that the cat has a mass of 5.00 kg (which is not provided in the question but can be inferred) and the acceleration due to gravity is 9.80 m/s², the force at which the cat falls can be calculated as follows:
T = mg = (5.00 kg) (9.80 m/s²) = 49.0 N.
Therefore, the correct answer to the question is D. 49 N.
The probable question may be:
What is the force at which the cat falls, with 5 kg mass?
A. 5.88 N
B. 19.6 N
C. 39.2 N
D. 49 N