Final answer:
The ion-electron equation for the oxidation reaction when aluminum reacts with hydrochloric acid is 2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g). In this reaction, aluminum is oxidized from an oxidation state of 0 to +3, while hydrogen is reduced from an oxidation state of +1 to 0.
Step-by-step explanation:
When aluminum reacts with hydrochloric acid, the following ion-electron equation represents the oxidation reaction:
2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
In this reaction, aluminum (Al) is oxidized from an oxidation state of 0 to +3, while hydrogen (H) is reduced from an oxidation state of +1 to 0. The formation of aluminum chloride (AlCl₃) and hydrogen gas (H₂) is the result of this reaction.