Question

Some cooking pans are made of cast iron, which has a specific heat of 448 J/kg°C. How many joules are needed to raise the temperature of a 1.5 kg iron skillet from 22°C to 450°C?

Answer 1

To raise the temperature of a 1.5 kg iron skillet from 22°C to 450°C, 287616 Joules of heat energy is required. This is calculated using the formula Q = mcΔT, with the specific heat capacity of iron as 448 J/kg°C.

Step-by-step explanation:

To calculate the amount of heat required to raise the temperature of a 1.5 kg iron skillet from 22°C to 450°C, we can use the formula:

Q = mcΔT

where:

• Q is the heat energy (in joules),
• m is the mass of the skillet (in kilograms),
• c is the specific heat capacity (in J/kg°C), and
• ΔT is the change in temperature (in °C).

In this case, m = 1.5 kg, c = 448 J/kg°C, and ΔT = (450 – 22) °C. Plugging in the values:

Q = (1.5 kg) × (448 J/kg°C) × (450 – 22) °C

Q = (1.5 kg) × (448 J/kg°C) × (428 °C)

Q = 287616 J

Therefore, 288,240 Joules of energy is needed to raise the temperature of the 1.5 kg iron skillet from 22°C to 450°C.