Final answer:
The probability of selecting an even number or a multiple of 3 from numbers 1 to 10 is 7 out of 10, which equals 70% or 0.7. None of the given options match this result, suggesting an error in the question or answer choices.
Step-by-step explanation:
The question asks to find the probability of choosing an even number or a multiple of 3 when a number is randomly selected from 1 to 10. To solve this, we first list all the even numbers and multiples of 3 in this range:
- Even numbers: 2, 4, 6, 8, 10 (5 in total)
- Multiples of 3: 3, 6, 9 (3 in total)
Note that the number 6 is both even and a multiple of 3, so it should be counted only once. Adding the unique outcomes together, we get 2, 3, 4, 6, 8, 9, 10 which are 7 in total. Since there are 10 possible numbers to choose from, the probability is 7 out of 10, or 7/10.
As a reduced fraction, the probability can be expressed as 70% or 0.7, but given the provided options this answer is not listed. Hence, none of the given options A) 2/5, B) 1/2, C) 3/5, D) 2/3 are correct, indicating a possible error in the question or answer choices.