Question

A projectile is launched horizontally at a speed of 30. meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time t at horizontal distance d from the base of the platform. [Neglect friction.] Calculate the horizontal distance, d, if the projectile's total time of ight is 2.5 seconds. [Show all work, including the equation and substitution with units.]

Answer 1

The horizontal distance d, that a projectile travels when launched horizontally is given by d = vx * t, where vx is the horizontal velocity and t is the time of flight. For a projectile launched at 30 meters per second with a flight time of 2.5 seconds, the horizontal distance is 75 meters.

Step-by-step explanation:

To calculate the horizontal distance d that a projectile travels when launched horizontally from a platform, we only need to consider the horizontal component of its velocity since horizontal and vertical motions are independent in projectile motion (neglecting friction).

The formula for horizontal distance d in projectile motion is: d = vx * t, where vx is the horizontal velocity and t is the time of flight. Since the projectile is launched horizontally, its initial horizontal velocity is the same as its constant horizontal velocity throughout the motion.

Using the given values, we have: d = 30 m/s * 2.5 s = 75 meters. Therefore, the projectile travels a horizontal distance of 75 meters.