Final answer:
The element with the electron configuration notation 1s²2s²2p⁴ is Oxygen (option d).
Step-by-step explanation:
The element with the electron configuration notation 1s²2s²2p⁴ is Oxygen (option d).
The electron configuration 1s²2s²2p⁴ indicates that there are 4 valence electrons in Oxygen. The 1s and 2s subshells are filled, and in the 2p subshell, there are two electrons in one orbital and two electrons in the other.
By referring to the electron configuration and orbital diagrams, we can determine that Oxygen (atomic number 8) has 2 electrons in its 1s orbital, 2 electrons in its 2s orbital, and 4 electrons in its 2p orbitals. Therefore, the correct answer is Oxygen (option d).