Question

A box is being pulled with a rope at a constant acceleration of 2.5 m/s^2 for a total of 8.3 seconds. How far does the box travel during this time? Assume it starts from rest.

Answer 1

The box being pulled at a constant acceleration of 2.5 m/s² for 8.3 seconds travels a distance of 86.1125 meters, calculated using the kinematic equation for uniformly accelerated motion.

Step-by-step explanation:

The student asked how far a box travels when it is pulled with a rope at a constant acceleration of 2.5 m/s² for a total of 8.3 seconds, starting from rest. To find the distance traveled, we can use the kinematic equation for uniformly accelerated motion, which is:

s = ut + 0.5at²

Where:

• s is the displacement,
• u is the initial velocity (which is 0 since the box starts from rest),
• a is the acceleration,
• t is the time.

Plugging in the values, we get:

s = 0 * 8.3 + 0.5 * 2.5 * (8.3)²

s = 0 + 0.5 * 2.5 * 68.89

s = 86.1125 meters

Therefore, the box travels a distance of 86.1125 meters during this time.