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At equilibrium, the following is found: [SO3(g)] = 0.400 mol/L, [H2O(g)] = 0.480 mol/L,

and [H2SO4(1)] = 0.600molL
SO3(g) + H2O(g) + H2SO4(1)
Calculate the value of the equilibrium constant. (answer: 5.208333333)

User Cfreak
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1 Answer

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Final answer:

The question appears to contain a mistake in the reaction equation provided. To accurately calculate an equilibrium constant, a correct balanced chemical equation and associated reaction coefficients would be required. Due to the error, the calculation of the equilibrium constant cannot be completed without further clarification.

Step-by-step explanation:

The question asks us to calculate the equilibrium constant (Ke) for the reaction SO3(g) + H2O(g) ⇌ H2SO4(l). However, the provided reaction appears to be incorrect, as sulfur trioxide and water do not combine to form sulfuric acid through a simple combination. Instead, sulfur trioxide reacts with water vapor to form H2SO3, which can further react to form H2SO4. Nevertheless, if we consider the hypothetical scenario given, we would use the concentrations of SO3, H2O, and H2SO4 to calculate Ke.

The general expression for the equilibrium constant is Ke = [products]^coefficients / [reactants]^coefficients. Given that the reaction actually involved should be more complex and involve multiple steps, the problem cannot be solved as stated. Additional information or corrections would be required to proceed with an accurate calculation.

For a valid similar reaction such as 2SO2(g) + O2(g) = 2SO3(g), Ke would be calculated using the concentrations of the reactants and products at equilibrium. Since the reaction provided does not lead to the formation of H2SO4 directly from SO3 and H2O, and no coefficients are given, a calculation of Ke is not feasible here.

User Newkid
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