Question

Samantha is driving forward at 27 meters per second (m/s) on 1 pointthe highway. Suddenly, she sees a moose on the road andslams on her brakes to save her brand new Kia. Her carcomes to a stop (0 meters per second) within 6 seconds.What is the acceleration (or deceleration in this case)?4.5 m/s20 -4.5 m/s^2050 m/s^20-16 m/sOOther:​

Answer 1

The acceleration (or deceleration) of Samantha's car is -4.5 m/s^2.

Step-by-step explanation:

The acceleration (or deceleration) of Samantha's car can be calculated using the formula: acceleration = change in velocity / time taken. Since her car comes to a stop (0 meters per second) from a velocity of 27 meters per second, the change in velocity is -27 m/s (negative because it's a deceleration). The time taken is 6 seconds. So, the acceleration (or deceleration) is:

acceleration = -27 m/s / 6 s = -4.5 m/s^2

So, the correct answer is -4.5 m/s^2.