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Write the quadratic function that lays on the points (0, -2), (1, 0), and (2, 4).

a) f(x) = 2x^2 - 2x - 2
b) f(x) = -2x^2 + 4x - 2
c) f(x) = x^2 - 2x - 2
d) f(x) = -x^2 + 4x - 2

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Final answer:

The quadratic function that passes through the points (0, -2), (1, 0), and (2, 4) is f(x) = 2x^2 - 2.

Step-by-step explanation:

The quadratic function that passes through the points (0, -2), (1, 0), and (2, 4) can be determined by substituting these points into the general quadratic function equation y = ax^2 + bx + c. Let's substitute each point into the equation and solve for a, b, and c.

Substitute point (0, -2):

-2 = a(0)^2 + b(0) + c

-2 = c

Substitute point (1, 0):

0 = a(1)^2 + b(1) + c

a + b + c = 0

Substitute point (2, 4):

4 = a(2)^2 + b(2) + c

4 = 4a + 2b + c

Solving the system of equations:

From the first substitution, we have c = -2.

Substituting c = -2 into the second equation gives a + b - 2 = 0.

Substituting c = -2 into the third equation gives 4 = 4a + 2b - 2.

Simplifying these equations, we find a = 2, and b = 0.

Therefore, the quadratic function is f(x) = 2x^2 - 2.

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