Final answer:
The maximum range of a baseball thrown at 35.0 m/s is calculated using the projectile motion equation and considering the optimal angle of 45 degrees for maximum distance, which results in a range of 122.5 meters.
Step-by-step explanation:
The question asks about the maximum range of a baseball thrown at 35.0 m/s. To calculate this, we use the equation for projectile motion:
R = (v^2 × sin(2θ)) / g
where R is the range, v is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity (9.81 m/s^2).
For maximum range, we must use the angle that gives the largest value of sin(2θ), which is 45 degrees. Thus:
R = (35.0 m/s)^2 × sin(90 degrees) / 9.81 m/s^2
Calculating the above using sin(90 degrees) = 1, we get:
R = 122.5 meters
Therefore, the answer is a) 122.5 meters.