Question

Show two ways to evaluate a(b + c) if a = 2, b = 3, and c = 4.

A. 2(3 + 4) = 2(7) = 14.
B. a(b + c) = 2(3 + 4) = 2(7) = 14.
C. 2 — 7 = 14.
D. a — b + a — c = 2 — 3 + 2 — 4 = 6 + 8 = 14.

Answer 1

a(b+c) = 2(3+4) = 2(7) = 14

a(b+c) = a*b + a*c = 2*3 + 2*4 = 6 + 8 = 14

The first way uses the order of operations PEMDAS. The second method uses the distributive property.

Answer 2

To evaluate a(b + c) when a = 2, b = 3, and c = 4, you can use the distributive property of multiplication over addition to get the answer, which is 14.

Step-by-step explanation:

In order to evaluate a(b + c) when a = 2, b = 3, and c = 4, you can use the distributive property of multiplication over addition:

1. Option A: 2(3 + 4) = 2(7) = 14
2. Option B: a(b + c) = 2(3 + 4) = 2(7) = 14

Option C (2 - 7 = 14) and Option D (a - b + a - c = 2 - 3 + 2 - 4 = 6 + 8 = 14) are incorrect because they do not apply the correct order of operations or the distributive property.