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What is an equation of the line that passes through the points (2, -6) and (1, -1)?

Put your answer in fully reduced form.
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1 Answer

7 votes

first find the gradient.

y2 - y1 / x2 - x1 = ((-1) - (-6)) / (1 - 2) = 5 / -1 = -5

Then find the equation of the line

y - y1 = m(x - x1)

y - (-2) = -5(x - 2)

y + 2 = -5x + 10

y = -5x + 10 - 2

y = -5x + 8

So the equation of the line is y = -5x + 8

User Samie Bee
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