Question

You drop a rock off the Empire State Building. How far has it dropped and what is its speed after 11.5 seconds?

A) 62.5 meters, 112.5 m/s
B) 115 meters, 225 m/s
C) 132.25 meters, 241.5 m/s
D) 150 meters, 275 m/s

Answer 1

The rock dropped from the Empire State Building would travel a distance of 650.175 meters and would be traveling at a speed of 112.7 m/s after 11.5 seconds, assuming no air resistance. The provided answer choices do not match these calculations.

Step-by-step explanation:

When you drop a rock off the Empire State Building, we can calculate how far it has dropped and what its speed is after 11.5 seconds using the equations of freefall under Earth's gravity (assuming air resistance is negligible). The acceleration due to gravity (g) is 9.8 m/s2.

• The distance (d) traveled by the rock can be found using the equation d = 1/2 * g * t2, where t is the time. So, d = 1/2 * 9.8 m/s2 * (11.5 s)2 = 650.175 m.
• The speed (v) of the rock after 11.5 seconds can be found using v = gt, so v = 9.8 m/s2 * 11.5 s = 112.7 m/s.

None of the provided answer choices match the correct calculations, indicating a possible error in the options given. The correct answer is not listed among the options A to D.