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What is the equation of the line in slope-intercept form that passes through the point (-5, -6) and is parallel to y = -4x + 7?

Options:
A) y = -4x - 26
B) y = -4x + 6
C) y = 4x - 26
D) y = 4x + 6

1 Answer

1 vote

Final answer:

The equation of the line in slope-intercept form that passes through the point (-5, -6) and is parallel to y = -4x + 7 is y = -4x - 26.

Step-by-step explanation:

To find the equation of a line parallel to y = -4x + 7, we need to use the same slope as the given line. Since parallel lines have equal slopes, the slope of the line we are looking for is -4. We can then use the point-slope form of a linear equation, which is given by y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Plugging in the values (-5, -6) for (x1, y1) and -4 for m, we can simplify the equation to y - (-6) = -4(x - (-5)). Simplifying further gives y + 6 = -4x - 20, and finally rearranging to slope-intercept form gives y = -4x - 26. Therefore, the correct answer is y = -4x - 26 (Option A).

User Asaf Shveki
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