Final answer:
The cat, after initially running at a velocity of 7.0 m/s and accelerating at 2.0 m/s^2 for 3.0 seconds, is now running at a velocity of 13.0 m/s.
Step-by-step explanation:
To calculate how fast the cat is running after accelerating, we use the formula for final velocity, which is:
v = u + at
Where:
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- t is the time
The cat initially runs at 7.0 m/s (initial velocity u) and accelerates at +2.0 m/s2 (a) for 3.0 seconds (t). Plugging in the values:
v = 7.0 m/s + (2.0 m/s2 * 3.0 s)
v = 7.0 m/s + 6.0 m/s
v = 13.0 m/s
The cat is now running at 13.0 m/s after accelerating for 3.0 seconds.
Therefore, the correct answer is:
A) 13.0 m/s