Question

What volume will 2.0 moles of nitrogen occupy at 720 torr and 293 K?

A) 0.50 L
B) 1.00 L
C) 2.00 L
D) 4.00 L

Answer 1

The volume of 2.0 moles of nitrogen at 720 torr and 293 K is approximately 1.00 L.

Step-by-step explanation:

The volume of a gas can be calculated using the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

To find the volume of 2.0 moles of nitrogen at 720 torr and 293 K, we can rearrange the equation to solve for V:

V = (nRT) / P

Plugging in the values, we get:

V = (2.0 moles * 0.0821 L·atm/mol·K * 293 K) / 720 torr

V ≈ 1.00 L

Therefore, the answer is Option B) 1.00 L.