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What is the distance between the points A=(-2, -2) and Q=(-8, 3) in the coordinate plane? Round your answer to the nearest hundredth.

a) 7.81
b) 7.07
c) 6.32
d) 5.00

User RishiG
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1 Answer

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Final answer:

The distance between the points A=(-2, -2) and Q=(-8, 3) in the coordinate plane is approximately 7.81 units.

The correct option is A.

Step-by-step explanation:

To find the distance between the points A=(-2, -2) and Q=(-8, 3) in the coordinate plane, we can use the distance formula:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Using the coordinates of the points A and Q, we have:

d = sqrt((-8 - (-2))^2 + (3 - (-2))^2)

d = sqrt((-6)^2 + (5)^2)

d = sqrt(36 + 25)

d = sqrt(61)

The distance between the points A and Q is approximately 7.81 units.

User CyberRobot
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