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Two students are pulling a 15 kg bag of volleyball equipment in the same direction one using 45 N and the other using 60 N of force. The friction force between the bag and the floor is 15 N. What is the net force acting on the bag?

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Final answer:

The net force acting on a 15 kg bag of volleyball equipment being pulled by two students with forces of 45 N and 60 N, against a friction force of 15 N, is 90 N.

Step-by-step explanation:

When two students are pulling a 15 kg bag of volleyball equipment in the same direction, with one using 45 N and the other using 60 N of force, the combined pulling force is simply the sum of these two forces. The total pulling force is 45 N + 60 N = 105 N. However, we must also consider the force of friction working against this motion, which is given as 15 N. To determine the net force acting on the bag, we subtract the friction force from the total pulling force:

Net Force = Total Pulling Force - Friction Force
= 105 N - 15 N
= 90 N.

Therefore, the net force acting on the bag of volleyball equipment is 90 N in the direction that the students are pulling.

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